What total 5 digit numbers divisible by 4 can be formed using 1 2 3 4 5
Hence, the number of 5 digit numbers which are divisible by 4, with digits from the set {1, 2, 3, 4, 5} and the repetition of digits is allowed, is 25. Therefore, the correct answer is '625'.
How many 4 digit numbers can be formed using 1 2 3 4 5 and divisible by 4
Hence, the answer is 125.
How many 5 digit numbers can be formed using 1 2 3 4 5
Total number of numbers formed by the digits 1, 2, 3, 4, 5 without repetition is 5! =120.
How many 5 digit numbers can be formed using the digits 1 2 3 4 5 with repetition
Number of such numbers =120.
How many numbers from 1 to 1000 are divisible by 2 3 4 and 5
16 numbers
Detailed Solution
∴ Total 16 numbers from 1 to 1000 are divisible by 2, 3, 4 and 5. RRB NTPC Result, Cut Off for Pay Level 5 declared for RRB Chandigarh. For other RRBs, the results will be released. Earlier, the RRB had released the tentative schedule for the upcoming DV &Medical Examination for various posts..
How many 5 digit numbers can be formed from 0 1 2 3 4 5 divisible by 3
Therefore, total number formed =120+96=216.
How many 4 digit numbers can be formed using 1 2 3 4 5
Summary: The number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated is 120.
How many 5 digit numbers can be formed using the digits 1 2 3 4 5 6 and 7 if the digits of the numbers that are formed are distinct
The last two digits possible for the number to be a multiple of 4 are 32, 52, 72, 24. For each of these combinations, there are 6 different numbers possible. So, with this set of 5 digits we can have 24 different numbers. Thus a total of 60 such numbers can be formed.
How many 5 digit numbers can be formed using the digits 1 2 3 4 5 6 7 if repetition of digits is not allowed
Hence, in 2520 ways, 5-digit numbers can be formed using the digits 1, 2, 3, 4, 5, 6, 7 if the repetition of digits is not allowed.
How many 3 digit numbers can be formed from digits 1 2 3 4 and 5
60 ways
Thus, 3-digit numbers can be formed in 60 ways without repetition. Q.
How many numbers in 1000 are divisible by 5
Hence, there are 200 numbers which are multiples of 5 from 1 to 1000.
How many numbers between 1 and 1000 are divisible by 3 5 or 7
1~1000, there are 333 numbers can be divided by 3; there are 200 numbers can be divided by 5; there are 142 numbers can be divided by 7; However there are 66 numbers can be divided by both 3 and 5 (e.g. 15); there are 47 numbers can be divided by both 3 and 7 (e.g. 21); there are 28 numbers can be divided by both 5 and …
How many 3 digit numbers can be formed using 0 1 2 3 4 5 without repetition
Without repetition counting the number of 3digit numbers using digits from {0,1,2,3,4,5}: Count the number of 3-digit strings whose last digit is even. This gives 60−8=52 3-digit even numbers using digits from {0,1,2,3,4,5} without repetition.
How many five digit numbers can be formed using digits 0 1 2 3 4 5 which are divisible by 3 without any of the digits repeating
A five digit number divisible by 3 is to be formed using the numbers 0, 1, 2, 3, 4 and 5 without repetitions. The total number of ways this can be done is. (a) 216.
How many 4 digit numbers can be formed using 1 1 2 2 3 4
Expert-Verified Answer
102 numbers of 4-digit numbers will be formed. Choose the 2 digits that don't repeat in C(3,2) = 3 ways. Case 3: Permutations with 2 pairs of identical digit. Total: 24+72+6 = 102 ways.
How many 4 digit numbers can be formed from digits 1 2 3 4 and 5 if repetition of digits is allowed
Hence, the required number of numbers = 5 x 5 x 5 x 5 x 5 = 625. Q. How many numbers of four digits can be formed with the digits 1, 2, 3, 4, 5 if the digits can be repeated in the same number
How many 4 digit numbers can be formed using digits 1 2 3 4 and 5 i without repetition of digits
Summary: The number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated is 120.
How many numbers can be formed using all digits 1 2 3 4 3 2 1
So, the number of ways to fill up 3 even places=3! 2! =3. Hence, the required number of numbers =(6×3)=18.
How many 3-digit even numbers can be formed from 1 2 3 4 5 and 6 with no repetition
Thus, 3-digit even number can be formed in 108 ways.
How many numbers from 1 to 1000 are divisible by 2 3 and 5
Therefore, there are 734 positive integers which are divisible by at least 2, 3 or 5 from 1 to 1000.
How many numbers 1 to 1000 inclusive are divisible by 2 3 or 5
Therefore, there are 734 positive integers which are divisible by at least 2, 3 or 5 from 1 to 1000.
How many 3 digits can be formed from the digits 1 2 3 4 and 5 assuming that
Total possible numbers =5×4×3=60.
How many different 3 digit numbers can be formed using 1 2 3 4 and 5
Thus, 3-digit numbers can be formed in 60 ways without repetition.
How many 5 digit numbers can be formed using the digits 1,2 3 4 5 6 and 7 if the digits of the numbers that are formed are distinct
The last two digits possible for the number to be a multiple of 4 are 32, 52, 72, 24. For each of these combinations, there are 6 different numbers possible. So, with this set of 5 digits we can have 24 different numbers. Thus a total of 60 such numbers can be formed.
How many 4 digit numbers can be formed using digits 1,2 3 4 and 5 i without repetition of digits
Summary: The number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated is 120.
